# Line slope calculator 2x+4y=42

**Straight line given by points A[1; 10] and B[5; 8]**

## Calculation:

**Slope-intercept form of line:**y = -0.5x+10.5

**Canonical form of the line equation:**2x+4y-42 = 0

**Parametric form of the line equation:**

x = 4t+1

y = -2t+10 ; t ∈ R

**Slope:**m = -0.5

**Slope angle of line: φ =**-26°33'54″ = -0.4636 rad

**X intercept:**x

_{0}= 21

**Y intercept:**y

_{0}= q = 10.5

**Distance line from the origin:**d

_{0}= 9.3915

**The length of the segment AB: |AB| =**4.4721

**Vector: AB =**(4; -2)

**Normal vector: n =**(2; 4)

**Midpoint of the segment AB: M =**[3; 9]

**Perpendicular Bisector equation:**4x-2y+6 = 0

**Vector OA = (1; 10) ; |OA| = 10.0499**

**Vector OB = (5; 8) ; |OB| = 9.434**

**Scalar product OA .OB = 85**

**Angle ∠ AOB = 26°17'41″ = 0.4589 rad**